New Math Class 6 Exercise 1.4 Thinking Time Page 14
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Question
Find the smallest 4− digit number which is divisible by 21,56 and 63
Solution
Smallest number divisible by 21,56,63
Factors of 21=3×7
Factors of 56=2×2×2×7
Factors of 63=3×3×7
LCM=2×2×2×3×3×7=504
∴504 is the smallest number divisible by 21,56 and 63
Now, smallest 4-digit number=1000
1000=504×2-8
Remainder=8
But we need to find a number where the remainder is 0
Required number=1000+(504+8)=1000+512=1512
So,1512 is the smallest 4 digit number.
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